Home Sports Peshawar Zalmi defeat Lahore Qalandars by 4 wickets
Sports - March 5, 2019

Peshawar Zalmi defeat Lahore Qalandars by 4 wickets

ABU DHABI – Peshawar Zalmi have defeated Lahore Qalandars by four wickets in a last over thriller in the 25th match in Abu Dhabi on Tuesday.

Qalandars – without the injured AB de Villiers – struggled to 124-7 on a sluggish pitch but their bowlers hit back hard to reduce Zalmi to 20-5.

Thereafter, the heroics of Misbahul Haq (59* runs) and Daren Sammy (46 runs) – the highest for the wicket in PSL history – helped seal victory and a PSL 2019 playoff spot for Peshawar.

For Lahore Qalandars, Tymal Mills grabbed 3 wickets for 29 and Sameen Gul got two wickets for 17 runs.

In the first innings, Haris Sohail scored 43 runs and David Wiese was not out at 26 runs.

For Zalmi, Shaheen Afridi got three wickets and R . Ten Doeschate grabbed one wicket.

Misbahul Haq was declared Man of the Match for his match winning knock.


Leave a Reply

Your email address will not be published. Required fields are marked *

Check Also

Moody’s upgradation of Pakistan outlook affirms sound financial policies: Finance Ministry

ISLAMABAD (APP) – At the conclusion of the review for downgrade initiated on 14 May …